Question 1. Without actually performing the long division, state whether the following rational numbers will have a terminating decimal expansion or a non-terminating repeating decimal expansion: (i)13/3125 (ii)17/8 (iii)64/455 (iv)15/1600 (v)29/343 (vi)23/2³*5² (vii)129/2²* 57* 75 (viii)6/15 (ix)35/50 (x)77/210 Chapter 1: Real Numbers Maths Class 10 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. how to check for terminating ration number with long division, Without long division Check rational numbers terminating is solved by our expert teachers. You can get ncert solutions and notes for class 10 chapter 1 absolutely free. NCERT Solutions for class 10 Maths Chapter 1: Real Numbers is very essencial for getting good marks in CBSE Board examinations
Question 1. Without actually performing the long division, state whether the following rational numbers will have a terminating decimal expansion or a non-terminating repeating decimal expansion:
(i)13/3125 (ii)17/8 (iii)64/455 (iv)15/1600 (v)29/343 (vi)23/2³*5² (vii)129/2²* 57* 75 (viii)6/15 (ix)35/50 (x)77/210
Answer:
(i) 13/3125
Factorize the denominator we get
3125 =5 x 5 x 5 x 5 x 5 = 55
So denominator is in form of 5m so 13/3125 is terminating .
(ii) 17/8
Factorize the denominator we get
8 =2 x 2 x 2 = 2³
So denominator is in form of 2n so 17/8 is terminating .
(iii) 64/455
Factorize the denominator we get
455 =5 x 7 x 13
There are 7 and 13 also in denominator so denominator is not in form of 2n*5m . hence 64/455 is not terminating.
(iv) 15/1600
Factorize the denominator we get
1600 =2 x 2 x 2 x2 x 2 x 2 x 5 x 5 = 26 x 5²
so denominator is in form of 2n x 5m
Hence 15/1600 is terminating.
(v) 29/343
Factorize the denominator we get
343 = 7 x 7 x 7 = 7³
There are 7 also in denominator so denominator is not in form of 2n x 5m
Hence it is none - terminating.
(vi) 23/(2³ x 5²)
Denominator is in form of 2n x 5m
Hence it is terminating.
(vii) 129/(2² x 57 x 75 )
Denominator has 7 in denominator so denominator is not in form of 2n x 5n
Hence it is none terminating.
(viii) 6/15
divide nominator and denominator both by 3 we get 2/5
Denominator is in form of 5m so it is terminating.
(ix) 35/50 divide denominator and nominator both by 5 we get 7/10
Factorize the denominator we get
10=2 x 5
So denominator is in form of 2n x5m so it is terminating
(x) 77/210.
simplify it by dividing nominator and denominator both by 7 we get 11/30
Factorize the denominator we get
30=2 x 3 x 5
Denominator has 3 also in denominator so denominator is not in form of 2n x 5n
Hence it is none terminating.
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